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author | Eugeniy E. Mikhailov <evgmik@gmail.com> | 2024-11-19 13:00:14 -0500 |
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committer | Eugeniy E. Mikhailov <evgmik@gmail.com> | 2024-11-19 13:00:14 -0500 |
commit | 6187aede8dc13a4fc4d5fd5463574955d702d7f4 (patch) | |
tree | 26767b68a7df52a8cef24cb74cc88453d42725c8 /python_src | |
download | matlab_strawberryfields-6187aede8dc13a4fc4d5fd5463574955d702d7f4.tar.gz matlab_strawberryfields-6187aede8dc13a4fc4d5fd5463574955d702d7f4.zip |
initial release
Diffstat (limited to 'python_src')
-rw-r--r-- | python_src/williamson.py | 70 | ||||
-rw-r--r-- | python_src/xpxp_to_xxpp.py | 26 | ||||
-rw-r--r-- | python_src/xxpp_to_xpxp.py | 25 |
3 files changed, 121 insertions, 0 deletions
diff --git a/python_src/williamson.py b/python_src/williamson.py new file mode 100644 index 0000000..19a2f5f --- /dev/null +++ b/python_src/williamson.py @@ -0,0 +1,70 @@ +def williamson(V, tol=1e-11): + r"""Williamson decomposition of positive-definite (real) symmetric matrix. + + See :ref:`williamson`. + + Note that it is assumed that the symplectic form is + + .. math:: \Omega = \begin{bmatrix}0&I\\-I&0\end{bmatrix} + + where :math:`I` is the identity matrix and :math:`0` is the zero matrix. + + See https://math.stackexchange.com/questions/1171842/finding-the-symplectic-matrix-in-williamsons-theorem/2682630#2682630 + + Args: + V (array[float]): positive definite symmetric (real) matrix + tol (float): the tolerance used when checking if the matrix is symmetric: :math:`|V-V^T| \leq` tol + + Returns: + tuple[array,array]: ``(Db, S)`` where ``Db`` is a diagonal matrix + and ``S`` is a symplectic matrix such that :math:`V = S^T Db S` + """ + (n, m) = V.shape + + if n != m: + raise ValueError("The input matrix is not square") + + diffn = np.linalg.norm(V - np.transpose(V)) + + if diffn >= tol: + raise ValueError("The input matrix is not symmetric") + + if n % 2 != 0: + raise ValueError("The input matrix must have an even number of rows/columns") + + n = n // 2 + omega = sympmat(n) + vals = np.linalg.eigvalsh(V) + + for val in vals: + if val <= 0: + raise ValueError("Input matrix is not positive definite") + + Mm12 = sqrtm(np.linalg.inv(V)).real + r1 = Mm12 @ omega @ Mm12 + s1, K = schur(r1) + X = np.array([[0, 1], [1, 0]]) + I = np.identity(2) + seq = [] + + # In what follows I construct a permutation matrix p so that the Schur matrix has + # only positive elements above the diagonal + # Also the Schur matrix uses the x_1,p_1, ..., x_n,p_n ordering thus I use rotmat to + # go to the ordering x_1, ..., x_n, p_1, ... , p_n + + for i in range(n): + if s1[2 * i, 2 * i + 1] > 0: + seq.append(I) + else: + seq.append(X) + + p = block_diag(*seq) + Kt = K @ p + s1t = p @ s1 @ p + dd = xpxp_to_xxpp(s1t) + perm_indices = xpxp_to_xxpp(np.arange(2 * n)) + Ktt = Kt[:, perm_indices] + Db = np.diag([1 / dd[i, i + n] for i in range(n)] + [1 / dd[i, i + n] for i in range(n)]) + S = Mm12 @ Ktt @ sqrtm(Db) + return Db, np.linalg.inv(S).T + diff --git a/python_src/xpxp_to_xxpp.py b/python_src/xpxp_to_xxpp.py new file mode 100644 index 0000000..01d0bf2 --- /dev/null +++ b/python_src/xpxp_to_xxpp.py @@ -0,0 +1,26 @@ + +def xpxp_to_xxpp(S): + """Permutes the entries of the input from xpxp ordering to xxpp ordering. + + Args: + S (array): input even dimensional square matrix or vector + + Returns: + (array): permuted matrix or vector + """ + shape = S.shape + n = shape[0] + + if n % 2 != 0: + raise ValueError("The input array is not even-dimensional") + + n = n // 2 + ind = np.arange(2 * n).reshape(-1, 2).T.flatten() + + if len(shape) == 2: + if shape[0] != shape[1]: + raise ValueError("The input matrix is not square") + return S[:, ind][ind] + + return S[ind] + diff --git a/python_src/xxpp_to_xpxp.py b/python_src/xxpp_to_xpxp.py new file mode 100644 index 0000000..940d8b8 --- /dev/null +++ b/python_src/xxpp_to_xpxp.py @@ -0,0 +1,25 @@ +def xxpp_to_xpxp(S): + """Permutes the entries of the input from xxpp ordering to xpxp ordering. + + Args: + S (array): input even dimensional square matrix or array + + Returns: + (array): permuted matrix or array + """ + shape = S.shape + n = shape[0] + + if n % 2 != 0: + raise ValueError("The input array is not even-dimensional") + + n = n // 2 + ind = np.arange(2 * n).reshape(2, -1).T.flatten() + + if len(shape) == 2: + if shape[0] != shape[1]: + raise ValueError("The input matrix is not square") + return S[:, ind][ind] + + return S[ind] + |