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-%\chapter*{Atomic Spectroscopy of the Hydrogen Atom}
-%\addcontentsline{toc}{chapter}{Hydrogen Spectrum}
-\documentclass{article}
-\usepackage{tabularx,amsmath,boxedminipage,epsfig}
- \oddsidemargin 0.0in
- \evensidemargin 0.0in
- \textwidth 6.5in
- \headheight 0.0in
- \topmargin 0.0in
- \textheight=9.0in
-
-\begin{document}
-\title{Atomic Spectroscopy of Hydrogen Atoms}
-\date {}
-\maketitle \noindent
- \textbf{Experiment objectives}: test and calibrate a diffraction grating-based spectrometer
- and measure the energy spectrum of atomic hydrogen.
-
-\subsection*{History}
-
- The observation of discrete lines in the emission spectra of
- atomic gases gives insight into the quantum nature of
- atoms. Classical electrodynamics cannot explain the existence
- of these discrete lines, whose energy (or wavelengths) are
- given by characteristic values for specific atoms. These
- emission lines are so fundamental that they are used to
- identify atomic elements in objects, such as in identifying
- the constituents of stars in our universe. When Niels Bohr
- postulated that electrons can exist only in orbits of discrete
- energies, the explanation for the discrete atomic lines became
- clear. In this laboratory you will measure the wavelengths of
- the discrete emission lines from hydrogen gas, which will give
- you a measurement of the energy levels in the hydrogen atom.
-
-\section*{Theory}
-
- The hydrogen atom is composed of a proton nucleus and a single
-electron in a bound state orbit. Bohr's groundbreaking hypothesis, that the
-electron's orbital angular momentum is quantized, leads directly to the
-quantization of the atom's energy, i.e., that electrons in atomic systems exist
-only in discrete energy levels. The energies specified for a Bohr atom of
-atomic number $Z$ in which the nucleus is fixed at the origin (let the nuclear
-mass $\rightarrow \infty$) are given by the expression:
-\begin{equation}\label{Hlevels_inf}
-E_n=- \frac{2\pi^2m_ee^4Z^2}{(4\pi\epsilon_0)^2h^2n^2}
- = -hcZ^2R_{\infty}\frac{1}{n^2}
-\end{equation}
-%
-where $n$ is the label for the {\bf principal quantum number}
- and $R_{\infty}=\frac{2\pi m_ee^4}{(4\pi\epsilon_0)^2ch^3}$ is called the
-{\bf Rydberg wave number} (here $m_e$ is the electron mass). Numerically,
-$R_{\infty}
-= 1.0974 \times 10^5 cm^{-1}$ and $hcR_{\infty} = 13.605 eV$.
-
-An electron can change its state only by making a transition ("jump") from an
-``initial'' excited state of energy $E_1$ to a ``final'' state of lower energy
-$E_2$ by emitting a photon of energy $h\nu = E_1 - E_2$ that carries away the
-excess energy. Thus frequencies of spectral emission lines are proportional to
-the difference between two allowed discrete energies for an atomic
-configuration. Since $h\nu = hc/\lambda$, we can write for this case:
-\begin{equation} \label{Hlines_inf}
-\frac{1}{\lambda}=\frac{2\pi^2m_ee^4Z^2}{(4\pi\epsilon_0)^2ch^3}
-\left[\frac{1}{n_2^2}-\frac{1}{n_1^2}\right]=
-R_{\infty}Z^2\left[\frac{1}{n_2^2}-\frac{1}{n_1^2}\right]
-\end{equation}
-Based on this description it is clear that by measuring the frequencies (or
-wavelengths) of photons emitted by an excited atomic system, we can glean
-important information about allowed electron energies in atoms.
-
-To make more accurate calculation of the Hydrogen spectrum, we need to take
-into account that a hydrogen nucleus has a large, but finite mass, M=AMp (mass
-number A=1 and Mp = mass of proton)\footnote{This might give you the notion
-that the mass of any nucleus of mass number $A$ is equal to $AM_p$. This is not
-very accurate, but it is a good first order approximation.} such that the
-electron and the nucleus orbit a common center of mass. For this two-mass
-system the reduced mass is given by $\mu=m_e/(1+m_e/AM_p)$. We can take this
-into account by modifying the above expression (\ref{Hlines_inf}) for
-1/$\lambda$ as follows:
-\begin{equation}\label{Hlines_arb}
-\frac{1}{\lambda_A}=R_AZ^2\left[\frac{1}{n_2^2}-\frac{1}{n_1^2}\right] \mbox{
-where } R_A=\frac{R_{\infty}}{1+\frac{m_e}{AM_p}}
-\end{equation}
-In particular, for the hydrogen case of ($Z=1$; $M=M_p$) we have:
-\begin{equation}\label{Hlines_H}
-\frac{1}{\lambda_H}=R_H\left[\frac{1}{n_2^2}-\frac{1}{n_1^2}\right]
-\end{equation}
-Notice that the value of the Rydberg constant will change slightly for
-different elements. However, these corrections are small since nucleus is
-typically several orders of magnitude heavier then the electron.
-
-
- Fig. \ref{spec} shows a large number of observed transitions between
- Bohr energy levels in hydrogen, which are grouped into series. Emitted photon
- frequencies (wavelengths) span the spectrum from the UV
- (UltraViolet) to the IR (InfraRed). Given our lack of UV or
- IR spectrometers, we will focus upon the optical spectral lines
- that are confined to the Balmer series (visible). These are
- characterized by a common final state of $n_2$ = 2. The
- probability that an electron will make a particular
-$n_1\rightarrow n_2$
- transition in the Balmer series can differ considerably,
- depending on the likelihood that the initial $n_1$ level is
- populated from above in the deexcitation process. This
- results in our being able to observe and measure only the following four
- lines: $6 \rightarrow 2$, $5 \rightarrow 2$, $4 \rightarrow 2$,
- and $3 \rightarrow 2$.
-
-
-\begin{figure}
-\includegraphics[width=0.7\linewidth]{spec.eps}
-\caption{\label{spec}Spectrum of Hydrogen. The numbers on the left show the
-energies of the hydrogen levels with different principle quantum numbers $n$ in
-$eV$. The wavelength of emitted photon in ${\AA}$ are shown next to each
-electron transition. }
-\end{figure}
-
-In this lab, the light from the hydrogen gas is broken up into its spectral
-components by a diffraction grating. You will measure the angle at which each
-line occurs on the left ($\theta_L$) and ($\theta_R$) right sides for as many
-diffraction orders $m$ as possible, and use Eq.(\ref{mlambda}) to calculate
-$\lambda$, using the following expression, derived in the Appendix.
-\begin{equation}\label{mlambda}
-m\lambda = \frac{h}{2}\left(\sin\theta_L+\sin\theta_R\right)
-\end{equation}
- Then the same
-expression will be used to check/calibrate the groove spacing $h$ by making
-similar measurements for a sodium spectral lines with known wavelengths.
-
-We will approach the data in this experiment both with an eye to confirming
- Bohr's theory and from Balmer's early perspective of someone
- trying to establish an integer power series linking the
- wavelength of these four lines.
-
-\section*{Spectrometer Alignment Procedure}
-
-Fig. \ref{expspec} gives a top view of the Gaertner-Peck optical spectrometer
-used in this lab.
-\begin{figure}
-\includegraphics[height=4in]{expspec.eps}
-\caption{\label{expspec}Gaertner-Peck Spectrometer}
-\end{figure}
-
-\subsubsection*{Telescope Conditions:} Start by adjusting the
-telescope eyepiece in
- or out to bring the crosshairs into sharp focus. Next aim the
- telescope out the window to view a distant object such as
- leaves in a tree. If the distant object is not in focus or if
- there is parallax motion between the crosshairs and the
- object, pop off the side snap-in button to give access to a
- set screw. Loosen this screw and move the ocular tube in or
- out to bring the distant object into sharp focus. This should
- result in the elimination of parallax. Tighten the set screw
- to lock in this focussed condition.
-
-\subsubsection*{Collimator Conditions:} Swing the telescope to view the collimator
- which is accepting light from the hydrogen discharge tube
- through a vertical slit of variable width. The slit opening
- should be set to about 5-10 times the crosshair width to
- permit sufficient light to see the faint violet line and to be
- able to see the crosshairs. If the bright column of light is
- not in sharp focus, you should remove a side snap-in button
- allowing the tube holding the slit to move relative to the
- collimator objective lens. Adjust this tube for sharp focus
- and for elimination of parallax between the slit column and
- the crosshairs. Finally, tighten the set screw.
-
-\subsubsection*{ Diffraction Grating Conditions:}
-\textbf{Appendix in this handout describes the operation of a diffraction
-grating!}
- Mount a diffraction grating which nominally
- has 600 lines per mm in a grating baseclamp.
- %Put a piece of
- % doublesided scotch tape on the top surface of the table plate.
- Fix the grating baseclamp to the table such that the grating's
- vertical axis will be aligned with the telescope pivot axis.
- Since the table plate can be rotated, orient the normal of the
- grating surface to be aligned with the collimator axis. Use
- the AUTOCOLLIMATION procedure to achieve a fairly accurate
- alignment of the grating surface. This will determine how to
- adjust the three leveling screws H1, H2, and H3 and the
- rotation angle set screw for the grating table.
-
- \textbf{AUTOCOLLIMATION} is a sensitive way to align an optical
- element. First, mount a ``cross slit'' across the objective lens of
- the collimator, and direct a strong light source into the
- input end of the collimator. Some of the light exiting through
- the cross slit will reflect from the grating and return to the
- cross slit. The grating can then be manipulated till this
- reflected light retraces its path through the cross slit
- opening. With this the grating surface is normal to the
- collimator light.
- Then, with the hydrogen tube ON and in place at
- the collimator slit, swing the rotating telescope slowly
- through 90 degrees both on the Left \& Right sides of the forward
- direction. You should observe diffraction maxima for most
- spectral wavelength, $\lambda$, in 1st, 2nd, and 3rd order. If these
- lines seem to climb uphill or drop downhill
- the grating will have to be rotated in its baseclamp to
- bring them all to the same elevation.
-
-\section*{Data acquisition and analysis}
-
-Swing the rotating telescope slowly and determine which spectral lines from
-Balmer series you observe.
-
-\emph{Lines to be measured:}
-\begin{itemize}
-\item \emph{Zero order} (m=0): All spectral lines merge.
-\item \emph{First order} (m=1): Violet, Blue, Green, \& Red on both Left \&
- Right sides.
-\item \emph{Second order} (m=2): Violet, Blue, Green, \& Red on
- both Left \& Right sides.
-\item \emph{Third order} (m=3): Blue, \& Green.
-\end{itemize}
- You might not see the Violet line due to its low
- intensity. Red will not be seen in 3rd order.
-
-Read the angle at which each line occurs, measured with the crosshairs centered
-on the line as accurately as possible. Each lab partner should record the
-positions of the spectral lines at least once. Use the bottom scale to get the
-rough angle reading in degrees, and then use the upper scale for more accurate
-reading in minutes. The width of lines is controlled by the Collimator Slit
-adjustment screw. If set too wide open, then it is hard to judge the center
- accurately; if too narrow, then not enough light is available
- to see the crosshairs. For Violet the intensity is noticeably
- less than for the other three lines. Therefore a little
- assistance is required in order to locate the crosshairs at
- this line. We suggest that a low intensity flashlight be
- aimed toward the Telescope input, and switched ON and OFF
- repeatedly to reveal the location of the vertical crosshair
- relative to the faint Violet line.
-
-\subsubsection*{ Calibration of Diffraction Grating:} Replace the hydrogen tube with
- a sodium (Na) lamp and take readings for the following two
- lines from sodium: $568.27$~nm (green) and $589.90$~nm (yellow). Extract from
- these readings the best average value for $h$ the groove
- spacing in the diffraction grating. Compare to the statement
- that the grating has 600 lines per mm. Try using your measured value
- for $h$ versus the stated value $600$ lines per mm in
- the diffraction formula when obtaining the measured
- wavelengths of hydrogen. Determine which one provide more accurate results, and discuss the conclusion.
-
-\subsubsection*{ Data analysis}
-\textbf{Numerical approach}: Calculate the wavelength $\lambda$ for each line
-observed. For lines observed in more than one order, obtain the mean value
-$\lambda_ave$ and the standard error of the mean $\Delta \lambda$. Compare to
-the accepted values which you should calculate using the Bohr theory.
-
-\textbf{Graphical approach}: Make a plot of $1/\lambda$ vs $1/n_1^2$ where
-$n_1$ = the principal quantum number of the electron's initial state. Put all
-$\lambda$ values you measure above on this plot. Should this data form a
-straight line? If so, determine both slope and intercept and compare to the
-expected values for each. The slope should be the Ryberg constant for
-hydrogen, $R_H$. The intercept is $R_H/(n_2)^2$. From this, determine the value
-for the principal quantum number $n_2$. Compare to the accepted value in the
-Balmer series.
-
-\textbf{Example data table for writing the results of the measurements}:
-
-\noindent
-\begin{tabular}{|p{1.in}|p{1.in}|p{1.in}|p{1.in}|}
-\hline
- Line &$\theta_L$&$\theta_R$&Calculated $\lambda$ \\ \hline
- m=1 Violet&&&\\ \hline
- m=1 Blue&&&\\ \hline
- m=1 Green&&&\\ \hline
- m=1 Red&&&\\ \hline
- m=2 Violet&&&\\ \hline
- \dots&&&\\ \hline
- m=3 Blue&&&\\ \hline
- \dots&&&\\\hline
-\end{tabular}
-
-\section*{Appendix: Operation of a diffraction grating-based optical spectrometer}
-
-%\subsection*{Fraunhofer Diffraction at a Single Slit}
-%Let's consider a plane electromagnetic wave incident on a vertical slit of
-%width $D$ as shown in Fig. \ref{frn}. \emph{Fraunhofer} diffraction is
-%calculated in the far-field limit, i.e. the screen is assume to be far away
-%from the slit; in this case the light beams passed through different parts of
-%the slit are nearly parallel, and one needs a lens to bring them together and
-%see interference.
-%\begin{figure}[h]
-%\includegraphics[width=0.7\linewidth]{frnhfr.eps}
-%\caption{\label{frn}Single Slit Fraunhofer Diffraction}
-%\end{figure}
-%To calculate the total intensity on the screen we need to sum the contributions
-%from different parts of the slit, taking into account phase difference acquired
-%by light waves that traveled different distance to the lens. If this phase
-%difference is large enough we will see an interference pattern. Let's break the
-%total hight of the slit by very large number of point-like radiators with
-%length $dx$, and we denote $x$ the hight of each radiator above the center of
-%the slit (see Fig.~\ref{frn}). If we assume that the original incident wave is
-%the real part of $E(z,t)=E_0e^{ikz-i2\pi\nu t}$, where $k=2\pi/\lambda$ is the
-%wave number. Then the amplitude of each point radiator on a slit is
-%$dE(z,t)=E_0e^{ikz-i2\pi\nu t}dx$. If the beam originates at a hight $x$ above
-%the center of the slit then the beam must travel an extra distance $x\sin
-%\theta$ to reach the plane of the lens. Then we may write a contributions at
-%$P$ from a point radiator $dx$ as the real part of:
-%\begin{equation}
-%dE_P(z,t,x)=E_0e^{ikz-i2\pi\nu t}e^{ikx\sin\theta}dx.
-%\end{equation}
-%To find the overall amplitude one sums along the slit we need to add up the
-%contributions from all point sources:
-%\begin{equation}
-%E_P=\int_{-D/2}^{D/2}dE(z,t)=E_0e^{ikz-i2\pi\nu
-%t}\int_{-D/2}^{D/2}e^{ikx\sin\theta}dx = A_P e^{ikz-i2\pi\nu t}.
-%\end{equation}
-%Here $A_P$ is the overall amplitude of the electromagnetic field at the point
-%$P$. After evaluating the integral we find that
-%\begin{equation}
-%A_P=\frac{1}{ik\sin\theta}\cdot
-%\left(e^{ik\frac{D}{2}\sin\theta}-e^{-ik\frac{D}{2}\sin\theta}\right)
-%\end{equation}
-%After taking real part and choosing appropriate overall constant multiplying
-%factors the amplitude of the electromagnetic field at the point $P$ is:
-%\begin{equation}
-%A=\frac{\sin (\frac{\pi D}{\lambda}\sin\theta)}{\frac{\pi
-%D}{\lambda}\sin\theta}
-%\end{equation}
-%The intensity is proportional to the square of the amplitude and thus
-%\begin{equation}
-%I_P=\frac{(\sin (\frac{\pi D}{\lambda}\sin\theta))^2}{(\frac{\pi
-%D}{\lambda}\sin\theta)^2}
-%\end{equation}
-%The minima of the intensity occur at the zeros of the argument of the sin. The
-%maxima are near, but not exactly equal to the solution of:
-%\begin{equation}
-% (\frac{\pi D}{\lambda}\sin\theta)=(m+\frac{1}{2})\pi \end{equation}
-%for integer $m$.
-%
-%The overall pattern looks like that shown in Fig. \ref{sinxox}.
-%\begin{figure}
-%\includegraphics[width=\linewidth]{sinxox.eps}
-%\caption{\label{sinxox}Intensity Pattern for Fraunhofer Diffraction}
-%\end{figure}
-
-%\subsection*{The Diffraction Grating}
-A diffraction grating is a common optical element, which consists of a pattern
-with many equidistant slits or grooves. Interference of multiple beams passing
-through the slits (or reflecting off the grooves) produces sharp intensity
-maxima in the output intensity distribution, which can be used to separate
-different spectral components on the incoming light. In this sense the name
-``diffraction grating'' is somewhat misleading, since we are used to talk about
-diffraction with regard to the modification of light intensity distribution to
-finite size of a single aperture.
-\begin{figure}[h]
-\includegraphics[width=\linewidth]{grating.eps}
-\caption{\label{grating}Intensity Pattern for Fraunhofer Diffraction}
-\end{figure}
-
-To describe the properties of a light wave after passing through the grating,
-let us first consider the case of 2 identical slits separated by the distance
-$h$, as shown in Fig.~\ref{grating}a. We will assume that the size of the slits
-is much smaller than the distance between them, so that the effect of
-Fraunhofer diffraction on each individual slit is negligible. Then the
-resulting intensity distribution on the screen is given my familiar Young
-formula:
-\begin{equation} \label{2slit_noDif}
-I(\theta)=\left|E_0 +E_0e^{ikh\sin\theta} \right|^2 = 4I_0\cos^2\left(\frac{\pi
-h}{\lambda}\sin\theta \right),
-\end{equation}
-where $k=2\pi/\lambda$, $I_0$ = $|E_0|^2$, and the angle $\theta$ is measured
-with respect to the normal to the plane containing the slits.
-%If we now include the Fraunhofer diffraction on each slit
-%same way as we did it in the previous section, Eq.(\ref{2slit_noDif}) becomes:
-%\begin{equation} \label{2slit_wDif}
-%I(\theta)=4I_0\cos^2\left(\frac{\pi h}{\lambda}\sin\theta
-%\right)\left[\frac{\sin (\frac{\pi D}{\lambda}\sin\theta)}{\frac{\pi
-%D}{\lambda}\sin\theta} \right]^2.
-%\end{equation}
-
-An interference on $N$ equidistant slits illuminated by a plane wave
-(Fig.~\ref{grating}b) produces much sharper maxima. To find light intensity on
-a screen, the contributions from all N slits must be summarized taking into
-account their acquired phase difference, so that the optical field intensity
-distribution becomes:
-\begin{equation} \label{Nslit_wDif}
-I(\theta)=\left|E_0
-+E_0e^{ikh\sin\theta}+E_0e^{2ikh\sin\theta}+\dots+E_0e^{(N-1)ikh\sin\theta}
-\right|^2 = I_0\left[\frac{sin\left(N\frac{\pi
-h}{\lambda}\sin\theta\right)}{sin\left(\frac{\pi h}{\lambda}\sin\theta\right)}
-\right]^2.
-\end{equation}
- Here we again neglect the diffraction form each individual slit, assuming that the
- size of the slit is much smaller than the separation $h$ between the slits.
-
-The intensity distributions from a diffraction grating with illuminated
- $N=2,5$ and $10$ slits are shown in Fig.~\ref{grating}c. The tallest (\emph{principle}) maxima occur when the denominator
- of Eq.(~\ref{Nslit_wDif}) becomes zero: $h\sin\theta=\pm m\lambda$ where
- $m=1,2,3,\dots$ is the diffraction order. The heights of the principle maxima are
- $I_{\mathrm{max}}=N^2I_0$, and their widths are $\Delta \theta =
- 2\lambda/(Nh)$.
- Notice that the more slits are illuminated, the narrower diffraction peaks
- are, and the better the resolution of the system is:
- \begin{equation}
-\frac{ \Delta\lambda}{\lambda}=\frac{\Delta\theta}{\theta} \simeq \frac{1}{Nm}
-\end{equation}
-For that reason in any spectroscopic equipment a light beam is usually expanded
-to cover the maximum surface of a diffraction grating.
-
-\subsection*{Diffraction Grating Equation when the Incident Rays are
-not Normal}
-
-Up to now we assumed that the incident optical wavefront is normal to the pane
-of a grating. Let's now consider more general case when the angle of incidence
-$\theta_i$ of the incoming wave is different from the normal to the grating, as
-shown in Fig. \ref{DGnotnormal}a. Rather then calculating the whole intensity
-distribution, we will determine the positions of principle maxima. The path
-length difference between two rays 1 and 2 passing through the consequential
-slits us $a+b$, where:
-\begin{equation}
-a=h\sin \theta_i;\,\, b=h\sin \theta_R
-\end{equation}
-Constructive interference occurs for order $m$ when $a+b=m\lambda$, or:
-\begin{equation}
-h\sin \theta_i + \sin\theta_R=m\lambda
-\end{equation}
-\begin{figure}[h]
-\includegraphics[width=\columnwidth]{pic4i.eps}
-%\includegraphics[height=3in]{dn.eps}
-\caption{\label{DGnotnormal}Diagram of the light beams diffracted to the Right
-(a) and to the Left (b).}
-\end{figure}
-Now consider the case shown in Fig. \ref{DGnotnormal}. The path length between
-two beams is now $b-a$ where $b=h\sin\theta_L$. Combining both cases we have:
-\begin{eqnarray} \label{angles}
-h\sin\theta_L-\sin\theta_i&=&m\lambda\\
-h\sin\theta_R+\sin\theta_i&=&m\lambda \nonumber
-\end{eqnarray}
-Adding these equations and dividing the result by 2 yields Eq.(\ref{mlambda}):
-\begin{equation}m\lambda=\frac{h}{2}\left(\sin\theta_L+\sin\theta_R\right)
-\end{equation}
-
-\end{document}
-\newpage