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1 files changed, 2 insertions, 2 deletions
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@@ -79,8 +79,8 @@ Imagine a metal wire connected to a cold reservoir at one end and a hot reservoi
\\
\textbf{Sensor calibration}: To obtain the radiation sensor readings for radiated power per unit area $S$ in the correct units ($W/m^2$), you need to use the voltage-to-power conversion factor $22~V/W$, and the area of the sensor $2mm\times2mm$:
\begin{displaymath}
-S[W/m^2]=\frac{\Delta V[mV]\cdot 10^{-3}[V/mV]}{22 [V/W]}\cdot \frac{1}{4\cdot
-10^{-6}[m^2]}
+S[W/m^2]=\frac{10^{-3}[V/mV]}{22 [V/W]}\cdot \frac{1}{4\cdot
+10^{-6}[m^2]} \cdot \Delta V[mV]
\end{displaymath}