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authorEugeniy Mikhailov <evgmik@gmail.com>2014-10-20 21:27:17 -0400
committerEugeniy Mikhailov <evgmik@gmail.com>2014-10-20 21:27:17 -0400
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downloadmanual_for_Experimental_Atomic_Physics-f2971f40194268633a1ea3d74e2acf98b4c2e654.tar.gz
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typos fixed thanks to Jacob
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@@ -365,7 +365,8 @@ wavelength value and uncertainty for each line, and then identify the initial an
states principle numbers ($n_1$ and $n_2$) for each line using Fig.~\ref{Hspec.fig}.
Make a plot of $1/\lambda$ vs $1/n_1^2$ where $n_1$ = the principal quantum number of the electron's
-initial state. Put all $\lambda$ values you measure above on this plot. You data point should form a
+initial state. Put all $\lambda$ values you measure above on this plot.
+Your data point should form a
straight line. From Equation~(\ref{Hlines_inf}) determine the physical meaning of both slope and
intercept, and compare the data from the fit to the expected values for each of them. The slope
should be the Rydberg constant for hydrogen, ${R_y}$. The intercept is ${R_y}/(n_2)^2$. From this,
@@ -607,7 +608,7 @@ not Normal}
Up to now, we assumed that the incident optical wavefront is normal to the pane of a grating. Let's
now consider more general case when the angle of incidence $\theta_i$ of the incoming wave is
-different from the normal to the grating, as shown in Fig. \ref{DGnotnormal}(a). Rather then
+different from the normal to the grating, as shown in Fig. \ref{DGnotnormal}(a). Rather than
calculating the whole intensity distribution, we will determine the positions of principle maxima.
The path length difference between two rays 1 and 2 passing through the consequential slits is $a+b$,
where: